solve equation 0.4x + 0.3y = 1.7 and 0.7x -0.2y=0.8 by substitution method
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The given equation are
0.4x+0.3=1.7 ……(1)
0.7x-0.2y=0.8 ..….(2)
multiply (1) by 2 and (2) by 3 and adding we get
0.8x+0.6y=3.4
2.1x-0.6y=2.4
+ - +
2.9x=5.8
x=5.8/2.9
x=2
putting x=2 in (1) we get
0.4(2)+0.3y=1.7
0.8+0.3y=1.7
0.3y=1.7-0.8
0.3y=0.9
y=0.9/0.3
y=3
hence x=2 and y=3
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