solve equation 190-58n+4n²=0
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190-58n+4n²=0
⇒ 4n² - 58n + 190 = 0
⇒ 2n² - 29n + 95 = 0
⇒ 2n² - 10n - 19n + 95 = 0
⇒ 2n(n-5) -19(n-5) = 0
⇒ (n-5) (2n-19) = 0
∴ either (n-5) = 0 or (2n-19) = 0
⇒ n = 5 or ⇒ n = 19/5
I hope it helps you ^_^
190-58n+4n²=0
⇒ 4n² - 58n + 190 = 0
⇒ 2n² - 29n + 95 = 0
⇒ 2n² - 10n - 19n + 95 = 0
⇒ 2n(n-5) -19(n-5) = 0
⇒ (n-5) (2n-19) = 0
∴ either (n-5) = 0 or (2n-19) = 0
⇒ n = 5 or ⇒ n = 19/5
I hope it helps you ^_^
Anurag19:
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