solve equation
2(3y-1) / 7+5y = 1/3
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2(3y-1) ÷7+5y=1/3
6y-2÷7+5y=1/3
By cross multiplication we have,
3(6y-2) = 7+5y
18y-6 = 7+5y
18y-5y = 7+6
13y= 13
y= 13/13=1
Value of y is 1
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