solve equation (2x + 1 ) is a factor of 2x^3 - 11x^2 - 4x +1
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Answered by
0
Hi!!!!!
2x+1=0
2x=-1
x=-1/2
=> 2x^3-11x^2-4x+1
=> 2(-1/2)^3-11(-1/2)^2-4(-1/2)+1
=> 2(-1/8)-11(1/4)+2+1
=> -1/4-11/4+2+1
=> -1-11+8+4 / 4
=>0/4
=>0
Hope it hlpzz... ●_●
##follow
=
2x+1=0
2x=-1
x=-1/2
=> 2x^3-11x^2-4x+1
=> 2(-1/2)^3-11(-1/2)^2-4(-1/2)+1
=> 2(-1/8)-11(1/4)+2+1
=> -1/4-11/4+2+1
=> -1-11+8+4 / 4
=>0/4
=>0
Hope it hlpzz... ●_●
##follow
=
Answered by
0
hey... here's ur solution,
let,
p( x) = 2 x³ - 11x² - 4 x +1
g ( x) = 2 x + 1
( Use Attachment )
hence
quotient = x² - 6x + 1
Hope it might be helpful !!
let,
p( x) = 2 x³ - 11x² - 4 x +1
g ( x) = 2 x + 1
( Use Attachment )
hence
quotient = x² - 6x + 1
Hope it might be helpful !!
Attachments:
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