solve equation
3r²+2r+3=0
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Answer:
Its not possible, at least you can't get a natural number as root.
Found this in the internet, hope it helps:
Find the Solution for
3x2+2x+3=0
using the Quadratic Formula where
a = 3, b = 2, and c = 3
x=−b±b2−4ac−−−−−−−√2a
x=−2±22−4(3)(3)−−−−−−−−−−√2(3)
x=−2±4−36−−−−−√6
x=−2±−32−−−−√6
The discriminant b2−4ac<0
so, there are two complex roots.
Simplify the Radical:
x=−2±42–√i6
x=−26±42–√i6
Simplify fractions and/or signs:
x=−13±22–√i3
which becomes
x=−0.333333+0.942809i
x=−0.333333−0.942809i
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