Question

solve equation 4x+7=47​

Answer 1

Answer :-

$\longmapsto\sf4x + 7 = 47$

Transposing 7 from LHS to RHS, changing it's sign,

$\longmapsto\sf4x = 47 - 7$

Subtracting 7 from 47,

$\longmapsto\sf4x = 40$

Transposing 40 from LHS to RHS, changing it's sign,

$\longmapsto\sf x = \dfrac{40}{4}$

Dividing 40 by 4,

$\longmapsto\sf x = 10$

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V E R I F I C A T I O N :-

• To check our answer, let's put 10 in the place of x and see whether LHS = RHS.

LHS

$\Rightarrow\rm 4x + 7$

Substituting the value of x,

$\Rightarrow\rm 4 \times 10 + 7$

Applying the BODMAS rule and multiplying 4 with 10 first,

$\Rightarrow\rm 40 + 7$

Adding 7 to 40,

$\Rightarrow\rm 47$

RHS

$\Rightarrow\rm 47$

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Since LHS = RHS,

Hence verified!

Answer 2

Answer:

x = 10

Step-by-step explanation:

4x+7 = 47

4x = 47-7

4x = 40

x = 40/4

x = 10