Question

solve equation√6x+1=√2x​

Answer 1

$\sqrt{6} x + 1 = \sqrt{2} x \\ \\ \sqrt{6}x - \sqrt{2} x = - 1 \\ \\ x( \sqrt{6} - \sqrt{2} ) = - 1 \\ \\ \underline{ \underline{x = \frac{ - 1}{( \sqrt{6} - \sqrt{2}) } }}$