Math, asked by sanjeevpatil20098, 4 months ago

solve equation√6x+1= √2x​

Answers

Answered by Anonymous
1

 \sqrt{6} x + 1 =  \sqrt{2} x \\  \\  \sqrt{6}x  -  \sqrt{2} x =  - 1 \\  \\ x( \sqrt{6}  -  \sqrt{2} ) =  - 1 \\  \\  \underline{ \underline{x =  \frac{ - 1}{( \sqrt{6}  -  \sqrt{2}) } }}

Answered by agampreet14
0

Step-by-step explanation:

6

x+1=

2

x

6

x−

2

x=−1

x(

6

2

)=−1

x=

(

6

2

)

−1

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