Math, asked by sushanthreddy4428, 2 days ago

solve equation by cramer's rule:7x+7y-7z=2,-x+11y+7z=1,11x+5y+7z=0

Answers

Answered by MysticSohamS
2

Answer:

hey here is your answer in above pics

pls mark it as brainliest

Attachments:
Answered by mahendrapatel92lm
0

Answer:

The solutions to the system of equations By using cramers rules arex=0, y=\frac{1}{6}, z=-\frac{5}{42}

Step-by-step explanation:

Cramer's rule is a formula for solving a system of linear equations with as many equations as unknowns that is effective whenever the system has a unique solution.

Given:

  • 7x+7y-7z=2,
  • -x+11y+7z=1,
  • 11x+5y+7z=0

$$\left[\begin{array}{c}7 x+7 y-7 z=2 \\-x+11 y+7 z=1 \\11 x+5 y+7 z=0\end{array}\right]$$

Matrix of Coefficients

$$M=\left(\begin{array}{ccc}7 & 7 & -7 \\-1 & 11 & 7 \\11 & 5 & 7\end{array}\right)$$

Answers column:

$$\left(\begin{array}{l}2 \\1 \\0\end{array}\right)$$

Replace the $x$-column values with the answer-column values

$$M_{x}=\left(\begin{array}{ccc}2 & 7 & -7 \\1 & 11 & 7 \\0 & 5 & 7\end{array}\right)$$

Replace the $y$-column values with the answer-column values

$$M_{y}=\left(\begin{array}{ccc}7 & 2 & -7 \\-1 & 1 & 7 \\11 & 0 & 7\end{array}\right)$$

Replace the $z$-column values with the answer - column values

$$M_{z}=\left(\begin{array}{ccc}7 & 7 & 2 \\-1 & 11 & 1 \\11 & 5 & 0\end{array}\right)$$

Find the derteminant

\begin{aligned}&D=1764 \\&D_{x}=0 \\&D_{y}=294 \\&D_{z}=-210\end{aligned}

Solve by using Cramer Rule

x=\frac{D_{x}}{D}, y=\frac{D_{y}}{D}, z=\frac{D_{z}}{D}

D denotes the determinant

x=\frac{D_{x}}{D}=\frac{0}{1764}

Simplify

$$x=0$$

y=\frac{D_{y}}{D}=\frac{294}{1764}

Simplify $\frac{294}{1764}:

z=\frac{D_{z}}{D}=\frac{-210}{1764}

Simplify $\frac{-210}{1764}: \quad-\frac{5}{42}$

The solutions to the system of equations are:

x=0, y=\frac{1}{6}, z=-\frac{5}{42}

Similar questions