Question

solve equation by using cramer's rule

4m+6n=54;3m +2n=28

don't spam..​

Answer 1

Answer:

$elo$

Step-by-step explanation:

Attachement refer kro ..

Hope it will be Helpful

Samchon lob you ❤️ xD

Answer 2

Given:

Two equation of variables m and n

4m+6n=54

3m+2n=28

To find:

The values of m and n using Cramer's rule

Solution:

The equations can be written as

2m +3n=27

3m+2n=28

Coefficient matrix

$D = \begin{vmatrix} 2 & 3 \\ 3 & 2\end{vmatrix}}\\\\=4-9=-5$

x-Matrix

$D_{x} = \begin{vmatrix} 27 & 3 \\ 28 & 2\end{vmatrix}}$

=54-84=-30

y-Matrix

$D_{y} = \begin{vmatrix} 2 & 27 \\ 3 & 28\end{vmatrix}}\\\\=56-81=-25$

To finally solve the required variables, we get the following results…

$m = \frac{D_x}{D} =\frac{-30}{-5}=6\\\\And \\\\n = \frac{D_y}{D} =\frac{-30}{-6}=5$

Result:

The final solution is:

m = 6 and n = 5

Formulas used:

1. Cramer's rule
2. Determinants of matrix