Math, asked by lal420053, 9 months ago

solve equation mathematics RS Aggarwal questions​

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Answered by pooja0524
0

Answer:

pls hit thank if it helps

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Answered by Anonymous
1

Step-by-step explanation:

(x-2)/4 +1/3 = x- (2x -1)/3

[3(x-2)+4]/12=3x - [(2x -1)]/3

(3x-2)/12=( x+1)/3

(3x-2)/4= ( x+1)

(3x-2)= 4( x+1)

3x-2= 4x+4

-2-4= x

x= -6

you can substitute the x value in the equation to get L.H.S.=RHS

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