solve equation mathematics RS Aggarwal questions
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pls hit thank if it helps
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Step-by-step explanation:
(x-2)/4 +1/3 = x- (2x -1)/3
[3(x-2)+4]/12=3x - [(2x -1)]/3
(3x-2)/12=( x+1)/3
(3x-2)/4= ( x+1)
(3x-2)= 4( x+1)
3x-2= 4x+4
-2-4= x
x= -6
you can substitute the x value in the equation to get L.H.S.=RHS
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