Solve equation : (z-4) (z+4) = (z+3) (z-7)+35
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It is well known that zn−1=(z−1)(∑n−1i=0zi)zn−1=(z−1)(∑i=0n−1zi). Substituting n=5n=5 gives us z5−1=(z−1)(1+z+z2+z3+z4)z5−1=(z−1)(1+z+z2+z3+z4). Thus, we have the following:
1+z+z2+z3+z4=z5−1z−1 (z≠1
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