Question

solve equations :- 5x+10=40​

Answer 1

Answer :-

• The value of x is 6.

To find :-

• The value of x.

Step-by-step explanation :-

$\longmapsto\sf5x + 10 = 40$

Transposing 10 from LHS to RHS, changing it's sign,

$\longmapsto\sf5x = 40 - 10$

Subtracting 10 from 40,

$\longmapsto\sf5x = 30$

Transposing 5 from LHS to RHS, changing it's sign,

$\longmapsto\sf x = \dfrac{30}{5}$

Dividing 30 by 5,

$\longmapsto\overline{\boxed{\sf x = 6}}$

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Verification :-

• To check our answer, let's put 6 in the place of x and check whether LHS = RHS.

LHS

$\rightarrow\rm 5x + 10$

Substituting the value of x,

$\rightarrow\rm 5 \times 6 + 10$

Applying the BODMAS rule and multiplying 5 with 6 first,

$\rightarrow\rm 30 + 10$

Adding 10 to 30,

$\rightarrow\rm 40$

LHS

$\rightarrow\rm 40$

• Since LHS = RHS,
• Hence verified!

Answer 2

Answer :

• Value of x is 6.

Solution :

Given Equation :

• 5x+10=40

To Find :

• The value of x.

Let's solve,

$\red\bigstar \bf 5x+10=40$

• Subtracting 10 from both the sides

$\implies\sf 5x+10 \green{-10}=40\green{-10}$

$\implies\sf 5x+ \cancel{10} \:\: \cancel{-10}=30$

$\leadsto \bf 5x = 30$

• Dividing both sides by 5

$\implies \sf \dfrac{5x}{\green{5}} = \dfrac{30}{\green{5}}$

$\implies \sf \dfrac{\cancel{5}\:x}{\cancel{5}} = \dfrac{^6\cancel{30}}{\cancel{5}}$

$::\implies \underline{\boxed{\pink{\sf x = 6}}}$

Hence,

Value of x is 6.

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Verification :

$\red\bigstar \bf 5x+10=40$

L.H.S

$\red\bigstar \bf 5x+10$

Putting x = 6

$::\implies \sf 5(6)+10$

• Multiplying 5 by 6

$::\implies \sf 30+10$

• Adding 30 and 10

$::\implies \sf 40$

= R.H.S

⠀⠀ ⠀ ⠀⠀Hence Verified!!

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