Math, asked by samarth31, 1 year ago

solve equations 5x+2_3(x+1)=_2(x+1)+5(x_2)


courtneymichell: 5*x-2/3*(x+5)-(7*x-(x-1))=0

Step by step solution :

Step 1 :

2
Simplify —
3
Equation at the end of step 1 :

2
(5x - (— • (x + 5))) - (6x + 1) = 0
3
Step 2 :

Equation at the end of step 2 :

2 • (x + 5)
(5x - ———————————) - (6x + 1) = 0
3
Step 3 :

Rewriting the whole as an Equivalent Fraction :

3.1 Subtracting a fraction from a whole

Rewrite the whole as a fraction using 3 as the denominator :

5x 5x • 3
5x = —— = ——————
1 3

Answers

Answered by shree35
0
5x+2-3x-1=-2x-1+5x-10
2x+1=3x-11
1+11=3x-2x
12=x
Answered by AashikChakravarthi
0
5x + 2 - 3x - 1 = -2x - 1 + 5x - 2
2x + 1 = 3x - 3
3 + 1 = 3x - 2x { Transposing 2x }
4 = x 
x = 4
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