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1)An obtuse angle of a rhombus is greater than twice at acute angles by 30 find the measure of each angel
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opposite angles of rhombus are equal.
so let acute angle be x then obtuse angle would be 2x +30 then by angle sum property of quadrilateral
x+2x+30 +x+2x+30 = 360°
6x +60=360
6x = 360-60 = 300
x = 300/6
x= 50
now obtuse angle= 2x +30 = 2*50 +30
=> 100+30=130
Acute angle =60
Obtuse angle= 130
Since opposite angles are equal therefore all 4 angles are
60,130,60,130
hope it helps.
If it helps mark it brainliest. Thanks
so let acute angle be x then obtuse angle would be 2x +30 then by angle sum property of quadrilateral
x+2x+30 +x+2x+30 = 360°
6x +60=360
6x = 360-60 = 300
x = 300/6
x= 50
now obtuse angle= 2x +30 = 2*50 +30
=> 100+30=130
Acute angle =60
Obtuse angle= 130
Since opposite angles are equal therefore all 4 angles are
60,130,60,130
hope it helps.
If it helps mark it brainliest. Thanks
Mankuthemonkey01:
Ok sry then
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