Math, asked by tinu21, 1 year ago

Solve example

1)An obtuse angle of a rhombus is greater than twice at acute angles by 30 find the measure of each angel

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Answered by Mankuthemonkey01
4
opposite angles of rhombus are equal.
so let acute angle be x then obtuse angle would be 2x +30 then by angle sum property of quadrilateral
x+2x+30 +x+2x+30 = 360°
6x +60=360
6x = 360-60 = 300
x = 300/6
x= 50
now obtuse angle= 2x +30 = 2*50 +30
=> 100+30=130
Acute angle =60
Obtuse angle= 130
Since opposite angles are equal therefore all 4 angles are
60,130,60,130
hope it helps.
If it helps mark it brainliest. Thanks

Mankuthemonkey01: Ok sry then
tinu21: its OK.
sahil939: thx
sahil939: it is right answer
Mankuthemonkey01: yes I know
Mankuthemonkey01: It is 50,130,50,130
Mankuthemonkey01: and wlcm
Mankuthemonkey01: 50,130,50,130 is right
Mankuthemonkey01: I have written 60,130,60,130 at last by mistake
sahil939: hmm
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