Question

solve f = a.b'+ c. What we have to do in this ​

Answer 1

Explanation:

Or,F(A,B,C)=A′B+B+C′(B+A)

[ B.1 = B ]

Or,F(A,B,C)=B(A′+1)+C′(B+A)

Or,F(A,B,C)=B.1+C′(B+A)

[ (A' + 1) = 1 ]

Or,F(A,B,C)=B+C′(B+A)

[ As, B.1 = B ]

Or,F(A,B,C)=B+BC′+AC′

Or,F(A,B,C)=B(1+C′)+AC′

Or,F(A,B,C)=B.1+AC′

[As, (1 + C') = 1]

Or,F(A,B,C)=B+AC′

[As, B.1 = B]

So,F(A,B,C)=B+AC′is the minimized form.