Solve (factorise) the below problem using a²- b² =(a-b) (a+b)
36(a+b)²-16(a-b)²
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Answer:
36(a+b) ²-16 (a- b) ²
= 36(a² + 2ab +b²) - 16(a² - 2ab + b²)
= 36a² + 72ab + 36b² - 16a² + 32ab -16b²
=20a² + 104ab + 20b²
Step-by-step explanation:
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36(a+b)^2 -16(a-b)^2
{6(a+b)}^2 -{4(a-b)}^2
{6(a+b)+4(a-b)} [6(a+b)-{4(a-b)}]
(6a+6b+4a-4b) (6a+6b-4a+4b)
(10a+2b) (2a+10b)
{6(a+b)}^2 -{4(a-b)}^2
{6(a+b)+4(a-b)} [6(a+b)-{4(a-b)}]
(6a+6b+4a-4b) (6a+6b-4a+4b)
(10a+2b) (2a+10b)
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