Question

solve fast i gave only 5 minutes ​

Answer 1

$\frac{16 \times 2 {}^{n + 1 \: \: \: \: \: \: \: \: - \: \: \: \: \: \: \: \: 4 \times 2 {}^{n} } }{16 \times 2 {}^{n + 2} \: \: \: - \: \: \: \: \: \: \: 2 \times2 {}^{n + 2} }$

$take \: 2 ^ {n + 2} \: as \: a \: common \: fator \: from \: the \: denominator$

$\frac{16 \times 2 {}^{n + 1} - 2 \times 2 \times 2 {}^{n} }{(16 - 2) \times (2 {}^{n + 2} }$

Simplify

$\frac{14 \times 2 {}^{n + 1} }{14 \times 2 {}^{n + 2} }$

$= \frac{2 \times 2 {}^{n} }{2 {}^{2} \times 2 {}^{n} }$

$= \frac{1}{2}$

This is your answer

I hope this helps you

Answer 2

Answer:

16×2

n+2

−2×2

n+2

16×2

n+1−4×2

n

take \: 2 ^ {n + 2} \: as \: a \: common \: fator \: from \: the \: denominatortake2

n+2

asacommonfatorfromthedenominator

\frac{16 \times 2 {}^{n + 1} - 2 \times 2 \times 2 {}^{n} }{(16 - 2) \times (2 {}^{n + 2} }

(16−2)×(2

n+2

16×2

n+1

−2×2×2

n

Simplify

\frac{14 \times 2 {}^{n + 1} }{14 \times 2 {}^{n + 2} }

14×2

n+2

14×2

n+1

= \frac{2 \times 2 {}^{n} }{2 {}^{2} \times 2 {}^{n} }=

2

2

×2

n

2×2

n

= \frac{1}{2}=

2

1