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i think the zeroes must be 5/3 and 5/6
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Yes you are correct that 5/3 and 5/6 are the two zeroes
Now Let 5/6= alpha and 5/3= beta
So, alpha × beta = constant term / coefficient of x^3
So, 5/6×5/3=(-2k-1)/2
25/18=(-2k-1)/2
(25×2)/18=(-2k-1)
50/18=(-2k-1)
-2k=50/18+1
-2k=(50+18)/18
-2k=68/18
-2k=34/9
k=34/9×1/-2
k=-34/18
k=-17/9
The value of k is -17/9
If you find it helpful please mark it as brainliest....
Now Let 5/6= alpha and 5/3= beta
So, alpha × beta = constant term / coefficient of x^3
So, 5/6×5/3=(-2k-1)/2
25/18=(-2k-1)/2
(25×2)/18=(-2k-1)
50/18=(-2k-1)
-2k=50/18+1
-2k=(50+18)/18
-2k=68/18
-2k=34/9
k=34/9×1/-2
k=-34/18
k=-17/9
The value of k is -17/9
If you find it helpful please mark it as brainliest....
Hetarth4:
If you it helpful please mark it as brainliest
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