Question

solve fast ,plz


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full explanation


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Answer 1

Answer:

$\huge\underline{ \underline{ \red{your \: \: answer}}}$

Explanation:

$Given \\ </p><p>a+b=14.................(1) \\ </p><p></p><p></p><p>c-d=10..................(2) \\ </p><p></p><p></p><p>a+c=15.................(3) \\ </p><p></p><p></p><p>b+d=16.................(4) \\ </p><p></p><p></p><p>Adding (3) and (4), we get \\ </p><p></p><p>a+b+c+d=31.........(5) \\ </p><p></p><p></p><p>Using (1) in (5), we get \\ </p><p></p><p>14+c+d=31 \\ </p><p></p><p>c+d=17................(6) \\ </p><p></p><p></p><p>Adding (2) and (6), we get \\ </p><p></p><p>c-d=10..................(2) \\ </p><p></p><p>c+d=17................(6) \\ </p><p></p><p>(c+d)+(c-d)=27\\</p><p></p><p>2c=27 \\ </p><p></p><p>c=13.5 \\ </p><p></p><p></p><p>(6) =>\\ </p><p></p><p>d=17-13.5 \\ </p><p></p><p>d=3.5 \\ </p><p></p><p></p><p>(3)=> \\ </p><p></p><p>a+13.5=15 \\ </p><p></p><p>a=15-13.5 \\ </p><p></p><p>a=1.5 \\ </p><p></p><p></p><p>(1) =>\\ </p><p></p><p>1.5+b=14 \\ </p><p></p><p>b=14-1.5 \\ </p><p></p><p>b=12.5 \\ \sf\red{a = 1.5 }\\ \sf\pink{b = 12.5} \\ \sf\purple{c = 13.5} \\ \sf\green{d = 3.5} \\ \\ \large\boxed{ \fcolorbox {red}{yellow}{hope \: it \: help \: you}}$

Answer 2

Answer:

:

\begin{lgathered}Given \\ a+b=14.................(1) \\ c-d=10..................(2) \\ a+c=15.................(3) \\ b+d=16.................(4) \\ Adding (3) and (4), we get \\ a+b+c+d=31.........(5) \\ Using (1) in (5), we get \\ 14+c+d=31 \\ c+d=17................(6) \\ Adding (2) and (6), we get \\ c-d=10..................(2) \\ c+d=17................(6) \\ (c+d)+(c-d)=27\\ 2c=27 \\ c=13.5 \\ (6) =>\\ d=17-13.5 \\ d=3.5 \\ (3)=> \\ a+13.5=15 \\ a=15-13.5 \\ a=1.5 \\ (1) =>\\ 1.5+b=14 \\ b=14-1.5 \\ b=12.5 \\ \sf\red{a = 1.5 }\\ \sf\pink{b = 12.5} \\ \sf\purple{c = 13.5} \\ \sf\green{d = 3.5} \\ \\ \large\boxed{ \fcolorbox {red}{yellow}{hope \: it \: help \: you}}\end{lgathered}

Given

a+b=14.................(1)

c−d=10..................(2)

a+c=15.................(3)

b+d=16.................(4)

Adding(3)and(4),weget

a+b+c+d=31.........(5)

Using(1)in(5),weget

14+c+d=31

c+d=17................(6)

Adding(2)and(6),weget

c−d=10..................(2)

c+d=17................(6)

(c+d)+(c−d)=27

2c=27

c=13.5

(6)=>

d=17−13.5

d=3.5

(3)=>

a+13.5=15

a=15−13.5

a=1.5

(1)=>

1.5+b=14

b=14−1.5

b=12.5

a=1.5

b=12.5

c=13.5

d=3.5

Explanation:

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