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Answered by
0
Answer:
I=3.68A
Explanation:
Finding the total rezistance:
R=3.6+6+3+1+3
R=16.6
then V=4.5v
Now finding the current through the ckt:
I=V/R
I=16.6/4.5
Total current I=3.68A.
i hope the answer is correct
Answered by
3
Since, resistors 1Ω and 3Ω are in series,
∴Req1=1+3=4Ω
Now, resistors 4Ω and 6Ω are in parallel,
∴Req2 =4Ω∥6Ω= ¼+⅙Ω=2.4Ω
Now, 3.6Ω,2.4Ω and 3Ω are again series,
∴Req3=(3.6+2.4+3)Ω=9Ω
Now, the current flowing the electric current
I=V÷Req3
Or,I=4.5÷9
Or,I=0.5
Therefore,I=0.5A
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