Question

solve fast plz its urgent​

Answer 1

Answer:

let the digits at tens place and ones place x and 9-x respectively

original number =10x+(9-x)

=9x+9

now interchange the digits:digit at ones place and tens place : x and 9-x respectively

new no.10(9-x)+x

=90-9x=9x+9+27

= 90-9x=9x+36

18x=54

x=54÷18

x=3

Answer 2

Answer:

let the once digit be 'x' and tens digit be 'y'

x+y=9

x=9-y

(10y+x)=(10x+y)+27

(10y+9-y)=(90-10y+y+27)

9y+9=117-9y

18y=108

y=6

x=3

the digit be 36 or 63