Solve find a and b
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Hey there !!
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√3–1/√3+1 = a–b√3
=> √3–1 / √3+1 × √3–1 / √3–1
=> (√3–1)² / [(√3)²–(1)²]
=> 3+1–2√3 / 3–1
=> 4–2√3 / 2
=> 2(2–√3) / 2
=> 2–√3
=> a–b√3
So, a = 2 and b = 1 .
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√3–1/√3+1 = a–b√3
=> √3–1 / √3+1 × √3–1 / √3–1
=> (√3–1)² / [(√3)²–(1)²]
=> 3+1–2√3 / 3–1
=> 4–2√3 / 2
=> 2(2–√3) / 2
=> 2–√3
=> a–b√3
So, a = 2 and b = 1 .
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