Question

solve following pair of linear equation by elimination method 2x+y=3
4x-y=9​

Answer 1

Step-by-step explanation:

2x−y=3 ------- (1)

4x+y=3 ------ (2)

From equation 1 :

y=2x−3

Substitute the value of y in equation 2 : 

4x+y=3

4x+2x−3=3

6x=3+3

x=66=1

Now, Substitute x=1 in equation 1 : 

2x−y=3

2(1)−y=3

2−3=y

y=−1

Therefore the solution is: x=1 and y=−1

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Answer 2

Value of x is 2 and y is - 1 if  2x+y=3 , 4x-y=9​

Given:

• Equations
• 2x+y=3
• 4x-y=9​

To Find:

Values of x and y using elimination method

Solution:

2x+y=3         Eq1

4x - y = 9      Eq2

Step 1:

Add both the equations to eliminate y

(2x + y) + (4x - y) = 3 + 9

=> 6x = 12

=> x = 2    ( divide both sides by 6)

Step 2:

2 * Eq1  - Eq2  -  to eliminate x

2(2x + y) - (4x - y) = 2(3) -  9

=> 4x + 2y - 4x + y = 6 - 9

=> 3y = - 3

=> y = - 1     ( divide both sides by 3)

Hence, Value of x is 2 and y is - 1