Question

solve following pair of linear equation by substitution method 3x+2y=1 ,x+3y=5​

Answer 1

Step-by-step explanation:

given eqs are

3x+2y=1 ->eq 1

x+3y=5 -> eq 2

from eq 2

x=5-3y ->eq 3

sub eq 3 in eq 1

3(5-3y)+2y=1

15-9y+2y=1

15-7y=1

15-1=7y

7y=14

y=2

sub y=2 in eq 1 or eq 2

taking eq 2

x+3(2)=5

x+6=5

x=5-6

x=-1

therefore values of X and y are -1,2