Question

Solve Following Subquestion .

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Answer 1

Answer:

• value of x = -32/11
• Value of y = 62/11

Step-by-step explanation:

According to the Question

• 14 = 3y + x

$\implies$ 3y + x = 14 --------(equation 1)

• 20 = 2y -3x

$\implies$ 2y - 3x = 20 ---------(equation 2)

Multiplying equation (1) by 3 we get

$\implies$ 42 = 9y +3x --------------(equation)

Now, adding equation (2) & (3) we get

$\implies$ 11y = 62

$\implies$ y = 62/11

Now, putting the value of y = 62/11 in equation (1) we obtain

$\implies$ 3(62/11) + x = 14

$\implies$ 186/11 + x = 14

$\implies$ x = 14 - 186/11

$\implies$ x = 154-186/11

$\implies$ x = -32/11

• Hence, the value of x = -32/11
• And, the value of y = 62/11

Answer 2

According to the question :-

• 14 = 3y + x

↦ 3y + x = 14 ( equation 1)

• 20 = 2y - 3x

↦- 3x + 2y = 20 ( equation 2 )

Now, we will multiply equation 1 from 3,

we will get,

$\leadsto \sf \: 3(3y + x) = 3 \times 14 \: \: \: \: \: \: \: \: \: \: \: \: \\ \leadsto \sf \: 9y + 3x = 42 \: ( equation \: 3)$

On adding equation 2 and 3, we get,

$\dashrightarrow \sf9y + 2y + 3x - 3x = 42 + 20 \\ \dashrightarrow \sf11y = 62 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \dashrightarrow \sf \: y = \frac{62}{11} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

Now, since we have obtained the value of y, we can easily find out the value of x by Substituting the value of y in equation 1,

So, after Substituting the value of y i.e. 62/11 in equation 1, we have,

$\dashrightarrow \sf3y + x = 14 \: \: \: \: \: \: \\\dashrightarrow \sf3( \frac{62}{11} ) + x = 14 \\ \dashrightarrow \sf \frac{186}{11} + x = 11 \: \: \: \\ \dashrightarrow \sf3y + x = 14 \: \: \: \: \: \: \\\dashrightarrow \sf3( \frac{62}{11} ) + x = 14 \\ \dashrightarrow \sf \: x = 14 - \frac{186}{11} \: \: \\ \dashrightarrow \sf \: x = \frac{154 - 186}{11} \\\dashrightarrow \sf \: x = \frac{ - 32}{11} \: \: \: \: \: \: \: \: \: \: \:$

$\sf \pink{\therefore x = \frac{ - 32}{11} } \\ \sf \orange{ y = \frac{62}{11}} \: \: \: \: \: \: \:$

NOTE :- For verification you can put the values of x and y in equation 1 and check whether L.H.S. = R.H.S.

If they are equal, then they would be verified.