Solve following system of equations 3x-y=0
5x+2y=22
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Answered by
0
Answer:
3x+2y+2=0 as equation1
5x+3y-22=0 as equation 2
multiply 1 equation by 3
9x+6y+6=0
multiply 2 equation by 2
10x+6y-44=0
subtract 1 equation from 2 one
10x+6y-44-9x-6y-6=0
x-50=0
x=50
put value of x in 1 equation
150+2y+2=0
152+2y=0
2y=-152
y=-76
Answered by
0
Answer:
xy=3 xy=29
Step-by-step explanation:
3x-y=0 5x+2y=22
xy=0+3 5x+2y=22
xy=3 7xy=22
xy=7+22
xy=29
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