Solve for:
1/log(pq)^x + 1/log(qr)^x + 1/log(rp)^x
Answers
Answer:
1
Step-by-step explanation:
1/log(pq)^x + 1/log(qr)^x + 1/log(rp)^x
let's solve it for 1/log(pq) ^x
1/ log (pq)^x
= 1 / x * log(pq)
= x * log(pq) ^-1 ( formula used
log x^n = n log x
log x^-n = - n log x)
= - x * log(pq)
= - x (log p + log q)
= x log q - x log p --------------(1)
similarly for 1/log(qr)^x
we have
= x log r - x log q ----------------(2)
and for 1/log(rp) ^x
we have
= x log p - x log r ----------------(3)
putting value of (1), (2), (3) in the equation we have
= x log q - x log p + x log r - x log q + x log p - x log r
= 1 (all terms cancel out)
Step-by-step explanation:
Gestapo, abbreviation of Geheime Staatspolizei (German: “Secret State Police”), the political police of Nazi Germany.