Math, asked by aryansachan2004, 1 month ago

Solve for:

1/log(pq)^x + 1/log(qr)^x + 1/log(rp)^x​

Answers

Answered by pranavmookonil
2

Answer:

1

Step-by-step explanation:

1/log(pq)^x + 1/log(qr)^x + 1/log(rp)^x

let's solve it for 1/log(pq) ^x

1/ log (pq)^x

= 1 / x * log(pq)

= x * log(pq) ^-1 ( formula used

log x^n = n log x

log x^-n = - n log x)

= - x * log(pq)

= - x (log p + log q)

= x log q - x log p --------------(1)

similarly for 1/log(qr)^x

we have

= x log r - x log q ----------------(2)

and for 1/log(rp) ^x

we have

= x log p - x log r ----------------(3)

putting value of (1), (2), (3) in the equation we have

= x log q - x log p + x log r - x log q + x log p - x log r

= 1 (all terms cancel out)

Answered by AttitudeQueenI3538
6

Step-by-step explanation:

Gestapo, abbreviation of Geheime Staatspolizei (German: “Secret State Police”), the political police of Nazi Germany.

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