Question

Solve for Θ:
2 sin²Θ=1/2, 0°< Θ < 90°

Answer 1

HERE IS YOUR ANSWER
See the attachment

Answer 2

2sin^2Θ=1/2
taking square roots on both sides
√2sinΘ=1/√2
sinΘ=1/√2*√2
sinΘ=1/2
therefore Θ=π/6 radians or 30 degrees