Solve for 2x-3y=10 and 4x-5y=15 by Elemination method
Answers
Answered by
3
Answer:
5(2x-3y=10)
3(4x-5y=15)
--------------
10x- 15y =50
12x-15y = 45
(-) (+) (-)
------------------
-2x +0 =5
X=5/-2
------------------
2(5/-2)- 3y =10
10/-2 -3y= 10
-3y=10-5
-3y= 5
y= 5/-3
Answered by
7
Answer:
x = -5/2 and y = -5
Step-by-step explanation:
2x-3y=10 ------equation 1
4x-5y=15 ------equation 2
Multiply eqn1 × 2 ; we get
4x-6y=20 ------equation 3
Subtract equation 2 and equation 3 ,
(4x-5y) - (4x-6y)=15-20
=> 4x - 5y - 4x + 6y = -5
=> y = -5
Substitute value of y in equation 1 ; we get
2x - (3×-5) = 10
2x -(-15) = 10
2x + 15 =10
2x = -5
=> x = -5/2
HOPE IT HELPS YOU...
PLEASE MARK MY ANSWER AS BRAINLIEST!!
HINT - You can substitute the values of x and y in any of the equations to check of LHS =RHS
Similar questions