Question

solve for 50 points
Maths Class 12 Determinants

The value of k is …………., if the area of the ∆PQR is 4 sq units whose vertices are P(k,0),Q(4,0) and R(0,2)​

Answer 1

Answer:

hope u understand....

Answer 2

ANSWER :

[k 0 1 ]

½ [4 0 1 ]

[0 2 1 ]

=±4

K=(0−2)−0(0)+1(8)=±8

−2K+8=±8

−2K=8−8

−2K=0

K=0

or −2K=−8−8

2K=16

K=8