solve for a (a-2)+[1/(a-2)]=3, a not equal to 2
Answers
Answered by
0
Answer:
a=( 7±√5) /2
Step-by-step explanation:
(a-2)+ 1/(a-2) = 3
let a-2=x then
x+1/x=3
Multiplying by x we get
x²+1=3x
x²-3x+1=0
Putting the value of x
(a-2)²-3(a-2)+1=0
a²-4a+4-3a+6+1=0
a²-7a+11=0
a= { 7±√(49-44) }/2
a=( 7±√5) /2
Answered by
12
Answer:
a = ( 7 ± √5 ) / 2
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