Math, asked by AnshitaRana809, 5 months ago

solve for a [a-2]+1by a-2=3 where a is not equal to2

Answers

Answered by sunehaarora167
0

Answer:

16 is the answer

Step-by-step explanation:

a-2=3

a=3+2=5

a[a-2]+1

5[5-2]+1

5[3]+1

15+1

16

Answered by 1234days
0

Answer:

a = 2 + 3 \\a = 5  \:  \:  \:  \:  \:  \:  \:  \:   \\(  {a}^{2}   -  2a) +1 \\ substituting \: the \: value \: of \: a \: .we \:  \\get \:  \:  \:  \:  \:  \:  \:  \:  \:  \\ (25 - 2 \times 5) + 1 \\( 25 - 10) + 1 \\ 15 + 1  \\ 16 \: answer

Step-by-step explanation:

16 answer

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