solve for a and b if a-b=11 and 4a-2b=-18
please show the steps.
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Explanation:
let a-b=11 be eqn no. 1
multiplying [1] ×2
2a-2b=22
4a-2b=-18(subtracting)
-2 a= 40
a= -20
substituting in (1)
-20-b=11
b=-31
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