Solve for A, B, C, given that the digits are distinct.
aa+bb+cc=abc
Answers
Answer:
=aa+bb+cc=ABC
=a^2+b^2+c^2=abc
=by cancellention.
you will get answers = ABC
hope you find it useful.
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or
=aa+bb+cc=abc
=by shifting alphabets on right side the sign becomes negative.,
so =a+b+c=a-a×b-b×c-c
so final answer is = ABC
Answer:
11+99+88=198
Explanation:
AA+BB+CC=ABC
Substitute Maximum Possible Values:
99+88+77=264
So,A is less than 300
(i.e.,) A is 1 or 2 (0 is not Possible because A,B,C are +ve numbers)
=====>Lets take Units digit:
A+B+C=C
A+B=0 (0 is a units digit)
Substitute A values:
1+B=0 or 2+B=0
1+9=0(10) or 2+8=0(10)
Above solution we get sum as 10 where 1 is a tens digit
and 0 is a units digit.
We get,
A=1 and B=9
(or)
A=2 and B=8
11+99+CC=19C (or) 22+88+CC=28C
110+CC=19C (or) 110+CC=28C 28C>264 (Maximum Possible
sum 99+88+77=264)
So,it is not Possible.
=======>Lets take Tens digit from 110+CC=19C:
1+C=9
C=8
Finally we get A=1 B=9 C=8
11+99+88=198
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