Math, asked by AmHarshuxD, 8 months ago

Solve for A if,
 \frac{sin \: a}{1 + cos \: a}  +  \frac{1 + cos \: a \: }{sin \: a}  = 4

Answers

Answered by Anonymous
43

\huge\bf\red{\underline{\underline{Solution}}}\::

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{\Large {\mathfrak {\orange{Given }}}}\begin{cases}\bf\blue{\dfrac {sin A}{1+cosA}+\dfrac {1+ cos A}{sin A} =4}\end{cases}

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\rm\underline\pink{Taking \ LCM}

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\longrightarrow\:\:\:\rm\purple {\dfrac {{sin}^{2}A+{(1+cosA)}^{2}}{sinA+sinA\:cosA}=4}

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\boxed{\rm{\blue{{sin}^{2}\theta+{cos}^{2}\theta=1}}}

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\longrightarrow\:\:\:\rm\green {\dfrac {1+1+2\:cosA}{sinA+sinA\:cosA)}=4}

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\longrightarrow\:\:\:\rm\purple {\dfrac {2+2\:cosA}{sinA+sinA\:cosA}=4}

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\longrightarrow\:\:\:\rm\green {\dfrac {2 \cancel {(1+cosA)}}{sinA\cancel {(1+cosA)}}=4}

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\longrightarrow\:\:\:\rm\purple {\dfrac {2}{sinA}=4}

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\longrightarrow\:\:\:\rm\green {2\:cosecA=2}

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\longrightarrow\:\:\: \rm\purple {cosecA=2}

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\longrightarrow\:\:\: \rm\underline\pink {cosec \:30^{\circ}=2}

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\star\:\:{\underline{\underline{\orange{\boxed{\sf{A \ = \ 30^{\circ} }}}}}}

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