Question

solve for a positive root of x-cosx x=0 by regular falsi method

Answer 1

Answer:

$x-\cos \left(x\right)x=0\quad :\quad x=0,\:x=2\pi n$

Step-by-step explanation:

$x-\cos \left(x\right)x=0$

$\mathrm{Factor\:out\:common\:term\:}-x$

$-x\left(-1+\cos \left(x\right)\right)=0$

$\mathrm{Using\:the\:Zero\:Factor\:Principle:\quad \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0$

$x=0\quad \mathrm{or}\quad \cos \left(x\right)-1=0$

$x=0$

$x=0,\:x=2\pi n$