Solve for A. tan A + tan 2 A + √3 tan A tan 2 A = √3
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Answer:
A = 20°
Step-by-step explanation:
tan A + tan 2 A + √3 tan A tan 2 A = √3
tan A + tan 2 A = √3
TanA + Tan2A/(1 - TanATan2A) = √3
Tan(A+2A) = √3 (∵ Tan(A+B) = TanA + TanB / 1 - TanATanB)
Tan3A = Tan60.
3A = 60
A = 20°
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