Math, asked by ranjan8270, 4 days ago

Solve for A the eqution 4 sin² A-3=0 if 0°​

Answers

Answered by Anonymous
0

Answer:

A = 60°

Step-by-step explanation:

4sin^{2}A - 3 = 0\\4sin^{2}A = 3\\sin^{2}A = \frac{3}4\\sinA = \sqrt{\frac{3}{4}}\\sinA= \frac{\sqrt{3}}{2}

We know from the trigonometric values of various angles that:

sin60 = \frac{\sqrt{3}}{2}

sinA = sin60

A = 60°

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