Question

Solve for a. Then Solve for b. I am severly suck on this

Answer 1

a = 10 , b = 6

Step-by-step explanation:

Consider there is no ${7}^{b}$

if we cancel out 7 ^b we have 7^2+8=7^a

i.e 7^10 = 7^a

Therefore, a = 10

We also see that 7^a/7^4 = 7^b

7^a - 4 = 7^b

7^10 - 4 = 7^b

Therefore, b = 6

note that we get a and b on comparing as base is same

while doing these type of sums try to get the base same

hope it helps you

Please mark as brainliest

Answer 2

Answer:

$\frac{ {7}^{2} \times {7}^{8} }{{7}^{4} }$

$\frac{ {7}^{10} }{ {7}^{4} } = \frac{ {7}^{a} }{ {7}^{4} }$

${7}^{10} = {7}^{a}$

a = 10

$\frac{ {7}^{10} }{ {7}^{4} } = {7}^{b}$

${7}^{6} = {7}^{b}$

b = 6

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