Question

Solve for (b^2 + 8 )(b^2 - 8)

Answer 1

$= ( {b}^{2} + 8)( {b}^{2} - 8) \\ = {b}^{4 } - 8{b}^{2} + 8 {b}^{2} - 64 \\ = {b}^{4} - 64$

Answer 2

Answer:

a

${a }^{2} + b {}^{2} = \frac{?}{?}$

a=2+8

b=2-8

c=?

a+b=b+a

2+8=10

b=2-8

c=1

b=12-8=4

$c = \frac{a}{b}$

c=

$c = \frac{10}{4}$

c=2.5