Question

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Two particles A and B of masses 20 g and 30 g respectively are at rest at a certain time. Because of the forces exerted by them on each other, the particles start moving. At a given instant, particle A is found to move towards east with a velocity of 6 cm/sec. What is the velocity of particle B at this instant (in cm/s)?

Answer 1

The velocity of B in this instant is -4 m/s.

Explanation:

It is stated that,

Mass of A (m1) = 20 g

Mass of B(m2) = 30 g

Velocity of A(v1) = 6 m/s

Velocity of B(v2) = ?

Initial velocity of A(u1) = 0

Initial velocity of B(u2) = 0

We know that,

m1u1 + m2u2 = m1v1 + m2u2

∴ According to the problem,

(20 × 0) + (30 × 0) = (20× 6) + (30× v2)

⇒ (20×6) + (30×v2) = (20×0)+(30×0)

⇒ 120 + 30v2 = 0

⇒ 30v2 = 0-120

⇒ 30v2 = -120

⇒ v2 = -120/30

⇒ v2 = -4 m/s.

∴ The velocity of B in this instant is -4 m/s.