Question

Solve for c, 55c + 13 ≤ 75c + 39

Answer 1

Step-by-step explanation:

55c+13<=75c+39

13-39<=75c-55c

-26<=20c

c>=-26/20

c>=-13/10

Answer 2

Answer:

$55c+13\le \:75c+39\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:c\ge \:-\dfrac{13}{10}\:\\ \:\mathrm{Decimal:}&\:c\ge \:-1.3\\ \:\mathrm{Interval\:Notation:}&\:[-\dfrac{13}{10},\:\infty \:)\end{bmatrix}$

Step-by-step explanation:

$55c+13\le \:75c+39$

$\gray{\mathrm{Subtract\:}13\mathrm{\:from\:both\:sides}}$

$55c+13-13\le \:75c+39-13$

$\gray{\mathrm{Simplify}}$

$55c\le \:75c+26$

$\gray{\mathrm{Subtract\:}75c\mathrm{\:from\:both\:sides}}$

$55c-75c\le \:75c+26-75c$

$\gray{\mathrm{Simplify}}$

$-20c\le \:26$

$\gray{\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}}$

$\left(-20c\right)\left(-1\right)\ge \:26\left(-1\right)$

$\gray{\mathrm{Simplify}}$

$20c\ge \:-26$

$\gray{\mathrm{Divide\:both\:sides\:by\:}20}$

$\dfrac{20c}{20}\ge \dfrac{-26}{20}$

$\gray{\mathrm{Simplify}}$

$c\ge \:-\dfrac{13}{10}$