solve for f 4(0.5f−0.25)=6+f
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Answered by
24
4(0.5f-0.25)=6+f
2f-1=6+f
2f-f=6+1
f=7
2f-1=6+f
2f-f=6+1
f=7
Answered by
10
4(0.5f−0.25)=6+f
2f-1= 6+f
2f-1-6-f = 0
f-7 = 0
f = 7
this is your answer
2f-1= 6+f
2f-1-6-f = 0
f-7 = 0
f = 7
this is your answer
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