Solve for k such that rhe equation evaluates to 0
2k + π = 138 + π
Answers
Answered by
6
2k - 138 = π - π
2k = 138
k = 138 / 2
k = 69
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Answered by
6
=> 2k + π = 138 + π
=> 2k = 138 + π - π
=> 2k = 138
=> k = 138/2 = 69
Check:-
=> 2k + π = 138 + π
=> 2× 69 + π = 138 + π
=> 138 + π = 138 + π
=> 138 -138 = π - π
=> 0 = 0
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