Math, asked by Anonymous, 1 year ago

Solve for k such that rhe equation evaluates to 0


2k + π = 138 + π​

Answers

Answered by Chaitanyahere
6

2k - 138 = π - π

2k = 138

k = 138 / 2

k = 69

follow me and mark as brainliest .

Answered by MяƖиνιѕιвʟє
6

\bold{\huge{\fbox{\color{Green}{Solution}}}}

=> 2k + π = 138 + π

=> 2k = 138 + π - π

=> 2k = 138

=> k = 138/2 = 69

Check:-

=> 2k + π = 138 + π

=> 2× 69 + π = 138 + π

=> 138 + π = 138 + π

=> 138 -138 = π - π

=> 0 = 0

&lt;marquee direction="left"&gt;</p><p>✌ Hope it helps uhh!! ✌ &lt;/marquee&gt;

Similar questions