Math, asked by DangerP, 1 month ago

solve for log
if you know only then​

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Answers

Answered by Anonymous
15

Topic:-

Logarithms

Given to find the value of :-

log_{10}\dfrac{bc}{a^2} +log_{10}\dfrac{ac}{b^2} +log_{10}\dfrac{ab}{c^2}

Solution :-

As we know that ,

logmnp_{10}= logm_{10} +logn_{10}+logp_{10}

So,

log_{10}\dfrac{bc}{a^2} +log_{10}\dfrac{ac}{b^2} +log_{10}\dfrac{ab}{c^2}

= log_{10}\dfrac{bc}{a^2} \times \dfrac{ac}{b^2} \times\dfrac{ab}{c^2}

= log_{10}\dfrac{\not{b}\not{c}}{\not{a^2}} \times\dfrac{\not{a}\not{b}}{\not{b^2}}  \times\dfrac{\not{a}\not{b}}{\not{c^2}}

= log1_{10}

As we know that = log1_{10} is 0

=0

So, the value of log_{10}\dfrac{bc}{a^2} +log_{10}\dfrac{ac}{b^2} +log_{10}\dfrac{ab}{c^2} = 0

So, option b is the correct

Used properties:-

logmnp_{10}= logm_{10} +logn_{10}+logp_{10}

 log1_{10} = 0

Know more properties :-

log_{a}\bigg(\dfrac{m}{n} \bigg)= log m_a- logn_{a}

log_aa= 1

log_{a}m^{n} = nlog_am

log_ab=\dfrac{1}{log_ba}

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