Math, asked by poorvakamathankar3, 8 months ago

solve for m :
(-5)^m-1÷(-5)^2=(-5)^-8​

Answers

Answered by spacelover123
15

Question

Find the value of 'm' in the equation ⇒ (-5)^{m-1}\div (-5)^{2} = (-5)^{-8}

\rule{300}{1}

Answer

Step 1: Since the bases are same we will take the exponents and solve the equation. Here we should keep this law of exponents in mind ⇒ a^{m} \div a^{n} = a^{m+n}

Let's solve your equation step-by-step.

(m-1)-2=-8

Step 1: Simplify both sides of the equation.

m-1-2=-8

m+-1+-2=-8

(Combine Like Terms)

(m)+(-1+-2)=-8

m+-3=-8

m-3=-8

Step 2: Add 3 to both sides.

m-3+3=-8+3

m=-5

Let's verify if the value of 'm' is (-5)

(-5)^{m-1}\div (-5)^{2} = (-5)^{-8}

(-5)^{-5-1}\div (-5)^{2} = (-5)^{-8}

(-5)^{-6}\div (-5)^{2} = (-5)^{-8}

Apply this law ⇒ a^{m} \div a^{n} = a^{m-n}

(-5)^{-6-2}=(-5)^{-8}

(-5)^{-8} = (-5)^{-8}

∴LHS = RHS

∴ m = -5 in the equation ⇒ \bf (-5)^{m-1}\div (-5)^{2} = (-5)^{-8}

\rule{300}{1}

Answered by sara122
0

Answer:

Answer

Question

Find the value of 'm' in the equation ⇒

Answer

Step 1: Since the bases are same we will take the exponents and solve the equation. Here we should keep this law of exponents in mind ⇒

Let's solve your equation step-by-step.

Step 1: Simplify both sides of the equation.

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