Question

Solve for n and y using substituting method
2n+3y=5 3n+4y=5

Answer 1

hope it will work for u

Step-by-step explanation:

$2n+3y=5$

$3n+4y=5$

multiply the first equation with 3

multiply the second equation with 2

$6n+9y=15$

$6n+8y=10$

now subbtract both the equations

the result will be

$0+y=5$

$y=5$

subsitute the value of y in any of the equations

$3n+4(5)=5$

$3n+20=5$

$3n=-15$

$n=-5$

Answer 2

$\Large{\underline{\underline{\mathfrak{\bf{Question}}}}}$

Solve for n and y using substituting method

2n+3y=5 3n+4y=5

$\Large{\underline{\underline{\mathfrak{\bf{Solution}}}}}$

$\Large{\underline{\mathfrak{\bf{\pink{Given}}}}}$

• 2n+3y=5 ..........(1)
• 3n+4y=5 ............(2)

$\Large{\underline{\mathfrak{\bf{\pink{Given}}}}}$

• Value of n and y

$\Large{\underline{\underline{\mathfrak{\bf{Explanation}}}}}$

by equation (1) ,

➠2n+3y=5

➠ 3y = 5 - 2n

➠ y = (5 - 2n)/3 ..........(3)

Keep value of y in equ(2)

➠ 3n + 4(5-2n)/3 = 5

➠ 9n + 20-8n = 15

➠ n = 15 - 20

➠ n = -5

keep value in equ(3),

➠ y = (5-2×-5)/3

➠ y = (5+10)/3

➠ y = 15/3

➠ y = 5

$\Large{\underline{\mathfrak{\bf{\pink{Thus}}}}}$

• Value of n = -5
• Value of y = 5

$\large{\underline{\underline{\mathfrak{\bf{Answer\:verification}}}}}$

[ keep value of x and y in equ(1) ]

➠ 2 × -5 + 3 × 5 = 5

➠ -10 + 15 = 5

➠ 5 = 5

L.H.S. = R.H.S.

That's proved .