solve for p and q, 2^p +3^q =17 ; 2^p+2 - 3^q+1=5
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Given equations are
2p+3q=−5 ....(1)
and 3p−2q=12 ....(2)
Therefore, 3p=12+2q⇒p=
3
12+2q
Substitute this value of p in equation (1), we get
2(
3
12+2q
)+3q=−5
⇒24+4q+9q=−15
⇒13q=−39
⇒q=−3
Put this vale of q in equation (3).
p=
3
12+2(−3)
⇒p=
3
12−6
⇒p=2
Therefore, the solution is p=2,q=−3.
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