solve for p and q simultaneously if:
6q + 7p = 3
2q + p = 5
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Answered by
2
6q+7p=3 x2
2q+p=5 x6
12q+14p=6......(1)
12q+6p=30.....(2)
subtracting eq(2) from eq( 1 )
0+8p =-24
p=-3(put the value of p=-3 in eq (1)
we get
q=4
2q+p=5 x6
12q+14p=6......(1)
12q+6p=30.....(2)
subtracting eq(2) from eq( 1 )
0+8p =-24
p=-3(put the value of p=-3 in eq (1)
we get
q=4
vipulraj615:
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Answered by
1
Hey mate :
Given :
6q + 7p = 3.........(1)
2q + p = 5............(2)
Then, p and q = ?
Now,
Eq..........(2) × 3 - Eq..........(1)
6q + 3p - 6q - 7p = 15 - 3
- 4p = 12
p = -3........(3)
From Eq.........(1) and Eq..........(3)
6q + (-21) = 3
6q = 3 +21_
6q = 24
q = 4
so,
p = -3.
q = 4.
Hope it Help you :)
Mark me as brainliest :-:
Given :
6q + 7p = 3.........(1)
2q + p = 5............(2)
Then, p and q = ?
Now,
Eq..........(2) × 3 - Eq..........(1)
6q + 3p - 6q - 7p = 15 - 3
- 4p = 12
p = -3........(3)
From Eq.........(1) and Eq..........(3)
6q + (-21) = 3
6q = 3 +21_
6q = 24
q = 4
so,
p = -3.
q = 4.
Hope it Help you :)
Mark me as brainliest :-:
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